> res = lm(time ~ age + gender, nym.2002) > summary(res) ... Coefficients: Estimate Std. Error t value Pr(>|t|) (Intercept) 241.450 6.250 38.63 < 2e-16 *** age 1.226 0.155 7.92 6.4e-15 *** genderMale -29.397 3.633 -8.09 1.7e-15 *** ...The difference is estimated to be a half-hour in total time.